First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have
Which means that the roots are
Next, we can expand the function definition:
In this form, it is much easier to compute the derivative:
If we evaluate the derivative in the points of interest, we have
This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation
is what we need. The three lines are:
This is the tangent at x = -2
This is the tangent at x = 0
This is the tangent at x = 1
Answer:
The mean of W is 55 ounces.
The standard deviation of W is 4.33 ounces.
Step-by-step explanation:
Let X: weight of a red delicious apple, and B: the weight of the box and packing material.
The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.
Applying the property of the mean: 
, the mean of W will be:
Applying the property of the variance: 
, the variance of W will be:
The mean standard deviation of W will be the squared root of V(W):
The mean of W is 55 ounces.
The standard deviation of W is 4.33 ounces.
0.0034, This should be the decimal
4y^1 + 6y^3...so factor out the GCF for another form
2y(2 + 3y^2) <== here is one form
another form would be to multiply ur equation by a multiple of ur GCF 2, such as 4
4(4y^1 + 6y^3) = 16y^1 + 24y^3 <== another form
