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2 years ago

Find the area of a circle with a diameter of 8m in terms of pi

Mathematics

1 answer:

tekilochka [14]2 years ago

5 0

Answer:

16π

Step-by-step explanation:

Area of a circle = πr²

8/2 = 4

Then you plug in 4 in to the formula above.

Have a great day :)

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A line of roses forms the diagonal of a rectangular flower garden. Th e line of roses is 18.4 m long, and one side of the garden

professor190 [17]

Given that the garden is rectangular and a line of roses form the diagonal 18.4 m long, we required to calculate the length of the perpendicular side.
Here we shall use the Pythagorean theorem.
c²=a²+b²
where c is the hypotenuse, a and b are the legs.
from the information given:
c=18.4 m
a=13 m
plugging this into our expression we get:
18.4²=13²+b²
next we solve for the value of b
b²=18.4²-13²
b²=338.56-169
b²=169.56
b=√169.56
b=13.0215
hence the length to the nearest tenth of a meter will be approximately 13.0 m

6 0

2 years ago

Find the perimeter of a rectangle whose lenth is 24cm and diagonal is 25cm

VikaD [51]

Answer:

using Pythagoras theorem

breadth = √25^2 -24^2

=√47

= 7cm

P = 24+7+24+7 = 62

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2 years ago

Test scores are normally distributed with a mean of 100 and a standard deviation of 15. an individual's iq score is found to be

Mnenie [13.5K]

Z score=(data value-mean)/standard deviation
z=(90-100)/15=-0.6666666667

6 0

3 years ago

Which strategy would you use to find 2+8? a) doubles plus 1. b)count on. c) doubles. d) doubles minus 1

Gekata [30.6K]

You would count on.

I hope i am right

8 0

3 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

2 years ago