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Alecsey [184]
4 years ago
13

A group of students calculated their average score at a spelling bee. They realized that if one of them scored 9 more points, th

eir average score would be 81 points. If one of them scored 3 points less, their average score would be 78 points. How many students were in the group?
Mathematics
1 answer:
alukav5142 [94]4 years ago
8 0

Answer: There are 4 students in the group.

Step-by-step explanation:

Let the number of students in the group be n

If one of them scored 9 more points , their average score would be 81 points.

So, our equation (1) will be

\frac{\sum x+9}{n}=81\\\\\sum x+9=81n

Similarly,

If one of them scored 3 points less, their average score would be 78 points.

So, our equation (2) will be

\frac{\sum x-3}{n}=78\\\\\sum x-3=78n

So, from equation (1) and (2) we get:

81n-9=\sum x=78n+3\\\\81n-9=78n+3\\\\81n-78n=3+9\\\\3n=12\\\\n=\frac{12}{3}\\\\n=4

Hence, there are 4 students in the group.

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Write the first four terms of the sequence defined by An=20-30(n-1)
monitta

The first four terms of sequence is 20, -10, -40, -70

<em><u>Solution:</u></em>

Given that we have to find the first four terms of sequence

<em><u>Given recursive formula is:</u></em>

a_n = 20 - 30(n-1)

<em><u>To find the first term, substitute n = 1</u></em>

a_1 = 20-30(1-1)\\\\a_1 = 20-30(0)\\\\a_1 = 20

Thus the first term of sequence is 20

<em><u>To find the second term, substitute n = 2</u></em>

a_2 = 20-30(2-1)\\\\a_2 = 20-30(1)\\\\a_2 = 20-30\\\\a_2 = -10

Thus the second term of sequence is -10

<em><u>To find the third term, substitute n = 3</u></em>

a_3 = 20-30(3-1)\\\\a_3 = 20-30(2)\\\\a_3 = 20-60\\\\a_3 = -40

Thus the third term of sequence is -40

<em><u>To find the fourth term, substitute n = 4</u></em>

a_4 = 20-30(4-1)\\\\a_4 = 20-30(3)\\\\a_4 = 20-90\\\\a_4 = -70

Thus the first four terms of sequence is 20, -10, -40, -70

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