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Verizon [17]
3 years ago
12

5. Divide 6/3 by 12. A. 1/2 B. 12/13 C. 13/12 D. 9/16

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0
The answer would be A. 1/2
leonid [27]3 years ago
7 0

Answer:

D hope this helps

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Can someone do #1 and #2 I don't really get the answer. My teacher hasn't explain anything. He just gave us the paper and we got
Elenna [48]
1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

= √x(7 + 2) + 2

= 9√x + 2  [ Final Answer ]

2) f(x) - g(x)

= 7√x + 4 - (2√x - 2)

= 7√x + 4 - 2√x + 2

= √x(7 - 2) + 6

= 5√x + 6   [ Final Answer ]

Hope this helps!
5 0
3 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
3 years ago
Read 2 more answers
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
determine if the ordered pair is a solution of the equation is (2 4) a solution of y = -3× - 2? true or false​
vesna_86 [32]

Answer:

False

Step-by-step explanation:

y = -3× - 2

4 = -3(2) - 2

4 = -6 - 2

4 = -8

4 0
3 years ago
4(5+ab) where a=-3.5 and b-0.8
lozanna [386]

Answer:

31.2

Step-by-step explanation:

4(5 + (- 3.5 × - 0.8)

4(5 + 2.8)

4(7.8)

31.2

6 0
3 years ago
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