Question

9. On a standardized test where the results are distributed normally, Elliete scored a 246. If the mean score was

Answer 1

Elliete's percentile rank is 96% for a score less than or equal to 246

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean,\sigma=standard\ deviation$

Given that μ = 182, σ = 36

For x ≤ 246:

$z=\frac{246-182}{36}=1.78$

From the normal distribution table:

P(x ≤ 246) = P(z < 1.78) = 0.9625 = 96%

Elliete's percentile rank is 96% for a score less than or equal to 246

Find out more on z score at: brainly.com/question/25638875