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Strike441 [17]
3 years ago
15

Pls help asap i need the help

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

-2.5 is correct answer

  1. Ans.=

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Solve for x: You must show your work (how you got your answer).<br><br> 8x + 5 = 35
valentinak56 [21]

Answer:

3.75 or 15/4

Step-by-step explanation:

8x+5=35

Subtract 5 from the left side to cancel it out, do the same thing to 35.

8x=30

Divide 8x by 8 to get x alone, do the same thing to 30.

x=3.75, or once you simplify 30/8, you get 15/4.

6 0
4 years ago
Simplify the expression. 10C7<br><br> A. 1<br><br> B. 3,628,800<br><br> C. 604,800<br><br> D. 120
Sophie [7]

Answer:

Combination

Step-by-step explanation:

Here by 10C7 we actually mean, C_{7}^{10}

And the formula for evaluating mCn is

=\frac{m!}{n!*(m-n)!}

Therefore

10C7 =  

=\frac{10!}{7!*(10-7)!} \\=\frac{10!}{7!*3!} \\

Where m! is called m factorial and can be evaluated as

m!= m*(m-1)*(m-2)*(m-3)*.......3*2*1

Hence

10!= 10*9*8......*3*2*1

7!= 7*8*6.....3*2*1

3!=3*2*1

With these we can evaluate

10C7

=\frac{10*9*8*7*.....3*2*1}{(3*2*1)*(7*6*5....3*2*1)}\\=\frac{10*9*8}{3*2*1} \\=\frac{10*3*4}{1} \\=120

Hence the answer is D

4 0
3 years ago
FInd the equation of the line
enot [183]

Answer:

y=-3/2x+3

Step-by-step explanation:

The slope is rise over run. It rises 3 and goes back -2 so the slope is -3/2 and it crosses the y-axis at 3 so the y-intercept is 3. The slope equation is y=mx+b.

6 0
3 years ago
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p
igor_vitrenko [27]

The required probability of success is given by 0.98906500

Assume the random variable X has a binomial distribution with the given probability of obtaining a success.
P(X<5), n=6, p=0.3

<h3>What is binomial distribution?</h3>

In binomial distribution for number trials we are investigating the probability of getting a success remain the same.


n = number of trails,
p = probability of success
x = the number of success

p(x<5) = P(x=0)+ p(x=1) + p(x=2)+p(x=3)+p(x=4)

= \binom{6}{0}(0.3)^0(1-0.3)^6+\binom{6}{1}(0.3)^1(1-0.3)^5+\binom{6}{2}(0.3)^2(1-0.3)^4+\binom{6}{3}(0.3)^3(1-0.3)^3+\binom{6}{4}(0.3)^4(1-0.3)^2

p(x<5) = 0.98906500

Thus the required  probability of success is given by 0.98906500

Learn more about Binomial distribution here:
brainly.com/question/14565246

#SPJ1



3 0
2 years ago
A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
3 years ago
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