Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation:
<u>Given</u>:
Given that FGH is a right triangle. The sine of angle F is 0.53.
We need to determine the cosine of angle H.
<u>Cosine of angle H:</u>
Given that the sine of angle F is 0.53
This can be written as,

Applying the trigonometric ratio, we have;
----- (1)
Now, we shall determine the value of cosine of angle H.
Let us apply the trigonometric ratio
, we get;
----- (2)
Substituting the value from equation (1) in equation (2), we get;

Thus, the cosine of angle H is 0.53
Answer:
<em>5
(4
x
+
5)</em>
That is the answer
5 is a factor if 20 and 25 and 4x + 5 cannot be furthor be simplified.