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True [87]
3 years ago
14

In triangle ABC, ∠A and ∠B are complementary, where cos A = 0.24. What is the measure, to the nearest degree of, ∠B?

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

m\angle B=14^o

Step-by-step explanation:

we know that

In this problem, if angle A and angle B are complementary, then triangle ABC is a right triangle

If two angles are complementary, then their sum is equal to 90 degrees and the cofunction identities state that the sine of one equals the cosine of the other and vice versa

so

sin(A)=cos(B)

cos(A)=sin(B)

we have

cos(A)=0.24

therefore

sin(B)=cos(A)=0.24

Find the measure of angle B

m\angle B=sin^{-1}(0.24)=14^o

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It is an isosceles triangle because it has two equal sides and a hypotenuse.

We have given that

A triangle has 2 sides that equal 5 inches. The other side equals 4 inches.

We have to determine the type of the triangle

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An isosceles triangle can be drawn in many different ways. It can be drawn to have two equal sides and two equal angles or with two acute angles and one obtuse angle.

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2 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Karo-lina-s [1.5K]

Let us find the co ordinates of each vertex of the triangle .

Vertex A ( in firs second quadrant) = ( -5 ,3)

vertex B in third quadrant = ( -5, -5)

vertex C in fourth quadrant = ( 4, -2)

let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0

AB= 8

BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90

BC = 9.48

AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106

AC= 10.29

Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77

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Answer:

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Step-by-step explanation:


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Please help thanks :)
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I think that is the answer

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