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Lelechka [254]
3 years ago
14

In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to

be memorized. Assume that the rate at which material is forgotten is proportional to the amount memorized. Suppose M denotes the total amount of a subject to be memorized and A(t) is the amount memorized in time t > 0. Determine a differential equation for the amount A(t) when forgetfulness is taken into account. (Assume the constants of proportionality for the rate at which material is memorized and the rate at which material is forgotten are k1 > 0 and k2 > 0, respectively. Use A for A(t).)
dA/dt =
Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

dA/dt = k1(M-A) - k2(A)

Step-by-step explanation:

If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)

Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:

Rate Memorized = k1(M-A)

Where k1 is the constant of proportionality for the rate at which material is memorized.

At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:

Rate forgotten = k2(A)

Where k2 is the constant of proportionality for the rate at which material is forgotten.

Finally, the differential equation for the amount A(t) is equal to:

dA/dt = Rate Memorized - Rate Forgotten

dA/dt = k1(M-A)  - k2(A)

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ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

Answer:

a. 150 + 51x < 100 + 55x

b. x > 12.5

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

Solving (b): Inequality Solution

150 + 51x < 100 + 55x

Collect Like Terms

51x-55x

-4x

Solve for x

x > -50/-4

x > 12.5

Solving (c): Interpret the solution in (b)

x > 12.5 implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

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