Answer:
The equation for the distance Jane's trainer bikes is 
.
Step-by-step explanation:
We have attached diagram for your reference.
Given:
Distance traveled on bike towards south = 16 miles
Distance she ran towards west = 12 miles
We need to find distance Jane's trainer bikes.
Solution:
Let the distance Jane's trainer bike be 'x'.
Now we will assume it to be right angled triangle.
So by Pythagoras theorem which states that;
"Square of the third side is equal to the sum of square of the other two sides."
framing in equation form we get;
Hence the equation for the distance Jane's trainer bikes is .
On solving we get;
Hence Jane's trainer bikes a distance of 20 miles.
(Answer: 120) angle EHF = 90 degrees+30 degrees=120 angle
Answer:
x =41.18114952
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
We know the hypotenuse and adjacent sides
cos theta = adjacent / hypotenuse
cos x = 14.3/19
taking the inverse cos of each side
cos^-1 (cos x) = cos ^-1 ( 14.3/19)
x =41.18114952
2. 6m
3. No, she has 2.8ft of fabric. She is 2.2 yards short... :)
Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:
The magnitude of vecor v is given to be 10. So we can write:
Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.
The point in option d, satisfies the equation.
Thus, the answer to this question is option D
