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stepan [7]
3 years ago
7

What is 30 digits of pi?

Mathematics
2 answers:
Sophie [7]3 years ago
5 0

Answer:

3.141592653589793238462643383279

Step-by-step explanation:

Please mark me as brainless hope It helps

posledela3 years ago
4 0

Answer:

3.1415926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 3421170679

Step-by-step explanation:

Go ogle

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PLEASE HELP I’LL MAKE YOU THE BRAINIEST <br> find the area of the trapezoid to the nearest tenth
murzikaleks [220]

Answer:

2.7m

Step-by-step explanation:

1.0m

0.5m

+1.2m

2.7m - answer

5 0
2 years ago
Let Pbe the set of polynomials. Let a, b, c and d be elements of Psuch that band dare non-zero elements of P Which of the follow
vazorg [7]
The answer is b the sun is a rational number
6 0
3 years ago
Which is a simplified form of the following expression? 6c^2+2.5d - d + 2c^2-3d
melisa1 [442]
By collecting like terms we have:

6 {c}^{2}  + 2 {c}^{2}  + 2.5d - d  - 3d \\  \\ 8 {c}^{2}  - 1.5d
3 0
3 years ago
HELP PLEASE !!!!!!!!!!
Arada [10]

Answer:

Answer B   (-\infty,1)U(1,2]

Step-by-step explanation:

Notice that the quotient of f(x)/g(x) is:

h(x)=\frac{\sqrt{2-x} }{x-1}

therefore, this new function imposes conditions due to the fact that it has a square root in the numerator and a binomial in the denominator both with the variable x. Then, in order for the root in the numerator to be defined, the argument inside the root must be larger than or equal to zero. That is:

2-x\geq 0\\2\geq x\\x\leq 2

So, this condition must be satisfied by the x-values of the domain.

Then we have the binomial in the denominator, which in order to be defined needs to be different from zero. Notice that the only x-value that could cause problems (render zero) is:

x-1=0\\x=1

Then, x\neq 1

So we have to eliminate the number 1 from the previous subset that required x smaller than or equal to 2.

The way to represent this Domain is then:  (-\infty,1)U(1,2]

8 0
3 years ago
Select all possible values for x in the equation x^3=375?
Helga [31]
<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

<h2>Why?</h2>

To solve the problem, we need to remember the following properties of the exponents and roots:

a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}

Then, we are given the expression:

x^{3}=375

So, finding "x", we have:

x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}

Hence, the possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

Have a nice day!

7 0
3 years ago
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