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4 years ago

Please help I'm very confused with this

Mathematics

1 answer:

Alchen [17]4 years ago

3 0

make all of the denominators the same

2 12/20 + 1 9/20 + 2 14/20 = 6 15/20 <-------- number model

simplify 6 3/4 <----- solution

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Find the distance, to the nearest tenth, from T(4-2) to U(-2,3)

kiruha [24]

Distance = SQRT(x^2+y^2)
x = 4 - (-2) = 6
y = 3 - 2 = 1

distance = SQRT(6^2 + 1^2) = SQRT(36+1) = SQRT(37) = 6.1

4 0

3 years ago

Use linear combination 4x-9y=1 -2x+3y=-1

kirill [66]

Answer:

(x, y) = (1, 1/3)

Step-by-step explanation:

The x-coefficient in the first equation is -2 times that in the second equation, so adding twice the second equation to the first will eliminate x:

(4x -9y) +2(-2x +3y) = (1) +2(-1)

-3y = -1 . . . . simplify

y = 1/3 . . . . . divide by -3

The y-coefficient in the first equation is -3 times the y-coefficient in the second equation, so adding 3 times the second equation to the first will eliminate y:

(4x -9y) +3(-2x +3y) = (1) +3(-1)

-2x = -2 . . . . . . simplify

x = 1 . . . . . . . . . divide by -3

The solution is (x, y) = (1, 1/3).

8 0

4 years ago

will give brainslist!!!!! A local high school has 1250 students in grades 9 through 12. Twenty-eight percent of the students in

UNO [17]

Answer:

175 ride the bus

Step-by-step explanation:

28% of 1250 = 350

350 ÷ 2 = 175

7 0

3 years ago

Read 2 more answers

How do I solve this equation quick with an easy method?

Pani-rosa [81]

Answer:

4/(3(x-2))

Step-by-step explanation:

3x^2-21x+30=3(x^2-7x+10)=3(x-5)(x-2)

3x-15=3(x-5)

----------------------------

So the common denominator must be 3(x-5)(x-2)

2(x-2)=2x-4

Add the numerators,

(2x-16)+(2x-4)=4x-16-4=4x-20

-----------------

(4x-20)/[3(x-5)(x-2)]

simplify 4x-20 into 4(x-5)

cancel out the (x-5)'s for both the denominator and the numerator

4/[3(x-2)]

3 0

3 years ago

Challenge Yael used to have a square garage with 370 ft ^2of floor space. She recently built an

Yuki888 [10]

Scale factor of area is the square of the scale factor of length

The required values are;

The length of one sides of the garage was originally approximately 19.2 ft.

The length of one of the sides of the garage is now approximately 23.6 feet long

The percentage increase in length is approximately 22.5 %

Reason:

The given parameters are;

The area of the square garage = 370 ft.²

The area of the new garage has 50% more space

Required;

Part A

The initial side length

The initial side length, given to the nearest tenth, s, is the square root of the area, A, given as follows;

s = √(370 ft.²) ≈ 19.2 ft.

Part B

The side was increased by 50%, to give,

370 + 0.5×370 = 555

The new area of the garage = 555 ft.²

The side length of the new garage, s = √(555) ≈ 23.6

The side of the garage now is 23.6 ft.

Part C

The percentage increase is given as follows;

$The \ percentage \ increase \ in \ length = \dfrac{New \ length - Initial \ length}{Initial \ length }$

$The \ percentage \ increase \ in \ length = \dfrac{\sqrt{555} - \sqrt{370} }{\sqrt{370} } \times 100 \approx 22.5 \%$

The percentage increase in length of the side of the garage is approximately 22.5 %

Learn more here:

brainly.com/question/7639412

3 0

3 years ago