A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb
</span>B) First, find the z-score:
z = (value - mean) / stdev
= (150 - 199) / 41
= -1.20
We need to find P(z > -1.20) = 1 - P(z < -1.20)
Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849
Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>
C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb
Let's repeat the steps of point B)
z = (187.5 - 199) / 41
= -0.29
P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141
</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%
D) The mean weight of skiers is 199lb, therefore:
number</span> of passengers = <span>load limit ÷ <span>mean weight of passengers
= 3750 </span></span><span>÷ 199
= 18.8
The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
Step-by-step explanation:
7e=the money she makes from earrings
13n=the money she makes from necklace
Question 1: 5/8=0.625=62.5% 13/22=about 0.59(repeats 09)=9%
22/30=about 0.73(repeats 3)=73% 12/25=0.45=45%
Store 3 had the greatest percentage of smart phones.
Question 2: 0.775/7.75%=0.775/0.0775=10
For mobile phone 3, it uses o.775 hour of battery life if 7.75% of battery is used.
It will reflect the same distance over the Y axis, from the right side of the graph to the left side of the graph.
Y - 4.5 = 12.2
your solving for y which means your trying to get rid of 4.5 so that y can equal something. The opposite of -4.5 would be +4.5, so you would add 4.5 to both sides to get
y = 16.7
So your answer would be
A. Add 4.5
and also dont' say your stupid because all you need is a little explanation and you'll get it, its very easy you just need to take the time to practice :-)
