Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
D
Step-by-step explanation: always remember that sign as irrational
Each number is increased by ten... umm idk any other answer you want
Total = 500 * ([(1 + .07)^26 -1] / .07) -500
Total = 500 * (<span><span>4.8073529249
</span>
/ .07) -500
</span>Total = 500 * (<span>68.6764703562) -500
</span>Total =
<span>
<span>
<span>
33,838.24
</span></span>
Source:
http://www.1728.org/annuity.htm
</span>
Answer:
5
Step-by-step explanation:
sqrt[(-8+3)² + (-6+6)²] = 5