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Andreas93 [3]
3 years ago
14

A baker uses 3/4 cup of honey in one of his cakes. There are 60 calories in 1/8 cup of honey. What equation would you use to fin

d out how many calories are in 3/4 cup of honey?
Mathematics
2 answers:
Murljashka [212]3 years ago
5 0

1/8 + 6/8 becaue 3/4 is equivalent to 6/8 and 1/8 + 6/8 = 360 calories

pogonyaev3 years ago
3 0
3/4 = 6/8
so u need 60*6, so
c=60*6 ?
c meaning calories
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Thad an Old Navy coupon for 25% off, so I went shopping for some new clothes.
creativ13 [48]

Discounted price before sales tax = 75/100 x (40 + 24 + 18 x 3) = 3/4 x (64 + 54) = 3/4 x 118 = $88.5

Total price inclusive of sales tax = 107/100 x 88.5 = $94.69

4 0
3 years ago
PLS HELP ME! Write a rule (function) for the data in this table.
yKpoI14uk [10]

Answer:

y = x - 3

<h3>How I know I'm correct:</h3>

if you plug in the numbers from the table, it checks out.

y = x - 3

0 = 3 - 3

0 = 0

y = x - 3

1 = 4 - 3

1 = 1

y = x - 3

2 = 5 - 3

2 = 2

and so on

5 0
3 years ago
What is the value of x
Tomtit [17]

Answer:

x=121

Step-by-step explanation:

because 180-121=59 and 180-59=121

3 0
3 years ago
What is the radius of a circle whose equation is (x 5)2 (y-3)3 42?O 2 unitso 4 unitsO 8 units16 unitsSave and ExitMark this and
dexar [7]

we know that

the equation of the circle is of the form

(x-h)^{2} +(y-k)^{2} =r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

in this problem we have

(x+5)^{2} +(y-3)^{2} =4^{2}

so

the center is the point (-5,3)

the radius is 4\ units

therefore

the answer is

The radius of the circle is equal to 4\ units

4 0
3 years ago
Read 2 more answers
Consider the quadratic equation x 2 = 4x - 5. How many solutions does the equation hase?
lara [203]

Answer:

The equation has 2 non real solutions.

Step-by-step explanation:

Given:

x ^2 = 4x - 5

To Find:

The solutions of the equation = ?

Solution:

Lets find the solution using the quadratic equation formula

x ^2 = 4x - 5

x^2-4x +5 = 0

x =   \frac{-b \pm  \sqrt{b^2-4ac}}{2a}

Here

a = 1

b =-4

c = 5

Now Substituting the values,

x =   \frac{-(-4) \pm  \sqrt{(-4)^2-4(1)(5)}}{2(1)}

x =   \frac{4\pm  \sqrt{16-20}}{2}

x =   \frac{4\pm  \sqrt{-4}}{2}

x =   \frac{4\pm  \sqrt{4}\times \sqrt{-1}}{2}

x =   \frac{4\pm 2 \sqrt{-1}}{2}

x =   \frac{4\pm 2i}{2}

x= \frac{4+2i}{2}                              x= \frac{4-2i}{2}

x= 2 + i                                  x= 2-i

5 0
3 years ago
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