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Thepotemich [5.8K]
2 years ago
5

7over10 subtract 5over12 in simplest form

Mathematics
1 answer:
Andrews [41]2 years ago
4 0

Answer: =\frac{17}{60}\quad \left(\mathrm{Decimal:\quad }\:0.28333\dots \right)

Step-by-step explanation:

\left(\frac{7}{10}\right)-\left(\frac{5}{12}\right)

=\frac{7}{10}-\frac{5}{12}

=\frac{42}{60}-\frac{25}{60}

=\frac{42-25}{60}

=\frac{17}{60}

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Kamila [148]
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5 0
2 years ago
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Smallest of 3 consecutive positive intergers if the product of the smaller two intergers is 5 less than 5 times the largest inte
amm1812

What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)

Three consecutive integers are . . . x,  x+1,  and  x+2

The smallest two are . . . x  and  x+1
    Their product is . . . . . x(x+1)

5 times the largest one is . . . 5(x+2)
      5 less than that is . . . . . . 5(x+2)-5

Now, the conditions of the problem say that    <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .

       Eliminate parentheses:    x² + x = 5x + 10 - 5
            Combine like terms:    x² + x = 5x + 5
Subtract 5x from each side:    x² - 4x = 5
Subtract  5  from each side:   <u>x² - 4x - 5 = 0</u>

You could solve that by factoring it, or use the quadratic equation.

Factored, it says that    (x + 1) (x - 5) = 0

From which       <em>x = -1</em>
             and      <em>x = +5</em>

We only want the positive results, so our three consecutive integers are

             5,  6,  and  7 .   

To answer the question, the smallest one is    <em><u>5 </u></em>.

<u>Check</u>:

   5 x 6  ? = ?  (7 x 5) - 5

       30  ? = ?  (35) - 5

         30   =   30

             yay !   


6 0
3 years ago
Can someone please answer 5, 6 and 7? Thank you.
Montano1993 [528]
Reduce a 24 cm by 36 cm photo to 3/4 original size.

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Let's reduce that to 3/4 size:  Mult. 864 cm^2 by (3/4).  Result:  648 cm^2.

We need to find new L and new W such that W/L = 2/3 and WL = 648 cm^2.

From the first equation we get W = 2L/3.  Thus, WL = 648 cm^2 = (2L/3)(L).

Solve this last equation for L^2, and then for L:

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Taking the sqrt of both sides, L = + 31.18 cm.  Then W must be 2/3 of that, or W = 20.78 cm.

Check:  is LW = (3/4) of the original 864 cm^2?  YES.


6 0
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Step-by-step explanation:

6 0
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