Which rate is greater? 18 pages in 36 minutes or 20 pages in 30 minutes. Explain your resoning

2 answers:

6 0

The second example is a greater rate of reading.

In order to come to that conclusion, I didn't do any figuring, ciphering,
numerating, or calculating of any kind. I just sat there and looked at
the question. I noticed that the second example is more pages than
the first one, but done in less time than the first one. So I know that
it must be a greater rate of cranking out the pages.

Helga [31]3 years ago

5 0

The first rate is 18/36 = 0.5 While the second rate is 20/30 = 0.6666666 So the second rate is greater.

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Answer:

The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.82, n = 225$ .

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$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.82*0.18}{225}} = 0.0256$

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