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Oksanka [162]
3 years ago
6

A number c decreased by 9 is less than or equal to 20 find c

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0
C-9<20

c=eleven or anything below
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Given h(x) = -x+5, solve for x when h(x) =0
Vedmedyk [2.9K]

Answer:

x=1

Step-by-step explanation:

4 0
3 years ago
Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

3 0
3 years ago
17
Alexandra [31]

Answer:

She saved $46

Step-by-step explanation:

1. Price for 3 adults would be $144

2. Price for 4 children would be $104

3. Total price for individual tickets would be $248

4. She bought 1 of [Combo 1] and 1 of [Combo 2]

5. Therefore, she paid $202

6. She saved $46

8 0
3 years ago
Which of thw following is equivalent to tosq root of -50
eimsori [14]
  • i = \sqrt{-1}
  • Product rule of radicals: √ab = √a x √b

Firstly, factor out i: i\sqrt{50}

Next, apply the product rule of radicals here as such:

i\sqrt{50}=i\sqrt{10\times 5}=i\sqrt{5\times 2\times 5}=5i\sqrt{2}

<u>Your answer is 5i√2, or the second option.</u>

8 0
3 years ago
Read 2 more answers
Write two numbers so that
lana [24]
-5 and 2 would work.
5 0
3 years ago
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