Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
Answer:
-17,-6and 1,-6
Step-by-step explanation:
Eight-year-olds can count to the highest number
Answer:
b. They can both be 90 degree angles
c. Acute angles are by definition 90 degrees, and acute is less than but not equal to 90 degrees
d. should be always
e. should be never (explanation: they have to be adjacent to be supplementary, and vertical angles are never adjacent)
Step-by-step explanation:
