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expeople1 [14]
2 years ago
9

Which expression has a value of 66? A. (16 ÷ 3.2) × 2 + 0.2 × (8 + 82) B. [(16 ÷ 3.2) × (2 + 0.2)] × 8 + 82 C. 16 ÷ [(3.2 × 2) +

(0.2 × 8)] + 82 D. [16 ÷ (3.2 × 2) + 0.2 × (8 + 82)]
Mathematics
1 answer:
Setler [38]2 years ago
8 0

Answer: none

Step-by-step explanation:

(A)

(16÷32/10) ×2 + 0.2×(90)

Using bodmas principle ; solve bracket

(16×10/32)×2 + (2/10×90)

10+18 =28

(B)

{(16÷32/10) × (2+2/10)} ×90

Open brackets

{(16×10/32) × (22/10)} ×90

(5×11/5) ×90

11×90 = 990

(C)

16÷{(32/10×2) + (2/10×8)} +82

Open brackets, solve division first, dolled by addition

16÷(32/5 + 8/5) +82

16÷(40/5) +82

16÷8 +82

2+82= 84

(D)

[16÷(32/10 ×2) + 0.2× (90)]

16÷ (32/5) + 2/10 ×90

Solve division

16×5/32 + 18

5/2 + 18

L.c.m of denominator (2&1) =2

(5+36) / 2 = 41/2

=20.5

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What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
3 years ago
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Sholpan [36]

Answer:

Larry must mow approximately 25 lawns before he starts making a profit

Step-by-step explanation:

8 0
3 years ago
What are the coefficients in 9/3+6+9a​
Norma-Jean [14]

Answer:

9

Step-by-step explanation:

cuz it has a variable by it

7 0
2 years ago
To make a sports drink for the football team, Jaylen filled \dfrac9{10}
Scilla [17]

The total gallons of sports drink Jaylen made using 9/10 of a large cooler with water and 6 cups of sports drink concentrate is 3.75 gallons

<h3>Total gallons</h3>

  • Water in the large cooler = 9/10

Space remaining = 1 - 9/10

= 10-9 / 10

= 1/10

1/10 = 6 cups

  • Total gallons of sport drink = x

6 cups / total = 1/10

6 × 10 = total × 1

60 cups = total

Cups to gallons:

16 cups = 1 gallon

Total gallons of sport drink, x = 60 cups / 16

= 3.75 gallons

Complete question:

To make a sports drink for the football team, Jaylen filled 9/10 of a large cooler with water. Then, he filled the remaining space with 6 cups of sports drink concentrate. How many gallons of sports drink did Jaylen make?

Learn more about total gallons:

brainly.com/question/26007201

#SPJ1

3 0
2 years ago
Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
2 years ago
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