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3 years ago

Find the area of the rectangle below (3x-2) (4x-7)

2 answers:

8 0

All we can do here is assume that the width and length of the rectangle in question are 3x-2 and 4x-7.

If and only if this assumption is correct, then the area is L * W, or

(3x-2)(4x-7) = 12x^2 -13x + 14.

Contact [7]3 years ago

4 0

To find the area, we have to use the F.O.I.L. method to solve (3x-2)*(4x-7)

-> 12x^2-21x-8x+14

= 12x^2 - 29x + 14

So the area of the rectangle would be 12x^2 - 29x + 14.

<span>Hope this helps. If you have any questions, place it in the comment section below.</span>

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1 year ago

Which operation results in a binomial? (3y ^ 6 + 4) (9y ^ 12 - 12y ^ 6 + 16)

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Given the expression, $(3y ^ 6 + 4) (9y ^ {12} - 12y ^ 6 + 16)$ , we want to know which sign placed in between the two polynomial will produce a binomial.

Using a plus (+) sign to check:

$= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\collect \ like \ terms\\= 9y^{12} +3y^6 - 12y^6 + 16+ 4\\= 9y^{12} - 9y^6 + 20\\$

From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

Using a plus (-) sign to check:

$= (3y ^ 6 + 4) - (9y ^ {12} - 12y ^ 6 + 16)\\= 3y ^ 6 + 4 - 9y ^ {12} + 12y ^ 6 - 16\\collect \ like \ terms\\= -9y^{12} +3y^6 +12y^6 + 4-16\\= -9y^{12} +15y^6 -12\\$

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<em>Hence none of the operations given results in a binomial</em>

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2 years ago

3(2y-3)=27can u solve this one

navik [9.2K]

3(2y-3)=27
6y-9=27
6y=36
y=6

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2 years ago