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zimovet [89]
3 years ago
9

F(x) = 3x; find f(7)

Mathematics
1 answer:
enot [183]3 years ago
5 0
F (7)=3 (7)=21 there's ur amswer
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HELP ⚠⚠⚠ MARKING BRAINLIEST, IF UR CONFUSED, I NEED HELP WITH QUESTION 9 BUT QUESTION 8 IS RELATED TO IT ⚠⚠⚠
4vir4ik [10]

Answer:

John has a sheet of paper that is 8 feet long. He cuts the length of paper into eighths, and then cuts the length of each of these \frac{1}{8} pieces into fourths. How many pieces does he have? How many inches long is each piece?

Step-by-step explanation:

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3 years ago
The frequency table shows the scores from rolling a dice 10 times.
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2 years ago
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A force of 7 lb is required to hold a spring stretched 9 in. beyond its natural length. How much work W is done in stretching it
Ymorist [56]

144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Force F=10 lb

From the hookes Law

F=kx

Therefore, calculate k for the spring for

10=k(\frac{4}{12}) = > k=\frac{120}{4}=30

Work done in stretching a spring through a length dx is

dW=F.dx = > dW=kxdx

For calculating the work done for stretching the spring to x=6in=(6/12)feet beyond the natural length, Integrate over the limits of x=0 to x=1/2

Therefore,

\int_{0}^{W}dW=\int_{0}^{0.5}kxdx = > W=\frac{1}{2}k[x^2]_{0}^{0.5}=\frac{1}{2}30 \times (0.5)^2=\frac{30}{8}

That is,

W=\frac{15}{4} ft-lb\\

The answer that is given is for stretching the spring to 4 inches.

Mass of 10 m of chain length is 80kg. This implies, Mass per unit meter length of the chain is

m_{l}=\frac{80}{10}=8kg/m

Consider a small length dx of the chain at the end point A. Work done in lifting the small length dx over the height of x meters is

dW=(8g)dx \times x=8gxdx

Now, integrate over the the value of x from

x=0 when end of the chain A is on the ground

x=6 when end of the chain A reaches 6 m above the ground

That is,

\int_{0}^{W}dW=\int_{0}^{6}8gxdx=8g [\frac{x^2}{2}]_{0}^{6}=4g(6^2-0^2)

W=4g \times 36=144g \ Joules

Hence,144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Learn more about Integration here brainly.com/question/2263647

#SPJ4

7 0
2 years ago
A catering service offers 7 appetizers, 8 main courses, and 11 desserts. A banquet chairperson is to select 5 appetizers, 5 main
adelina 88 [10]
Number of ways = 7C6*11C7*5C2 
<span>= 7*330*10 </span>
<span>= 23100</span> <span>C(7, 6)*C(11, 7)*C(5, 2) = 23,100

</span>
7 0
4 years ago
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