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zimovet [89]
3 years ago
9

F(x) = 3x; find f(7)

Mathematics
1 answer:
enot [183]3 years ago
5 0
F (7)=3 (7)=21 there's ur amswer
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How many ink cartridges can you buy with 150 dollars if one cartridge costs 15 dollars ?
musickatia [10]

Answer:

10

Step-by-step explanation:

Very easy equation if you know how to do it. All you need to do is divide your total amount of something (in this case "150" as that's our amount of "money we're given") by whatever the price or amount is. (In this case 15. Each cartridge costs $15. I'm not amazing at explaining things like this.. Sorry about that. If you have any questions about this feel free to let me know!)

So to put it "all together":

150 ÷ 15 = 10.

10 is your answer.

Hope this helps and have a nice day!

8 0
3 years ago
00:00
irina [24]

Answer:

the answer is 16

Step-by-step explanation:

its 16 because 2 quart= 8 cups

and 4pints = 8 cups

5 0
3 years ago
_+6 +2 = 6 + 10<br><br> Find the missing number
Sauron [17]
574=30303 equals that
4 0
3 years ago
Read 2 more answers
A student solved this problem and said the answer is quarts
kenny6666 [7]
B. no the answer isn't reasonable, it should be about 3 quarts.
3 0
3 years ago
a 15-foot telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 degre
scoundrel [369]

Answer:

The length of the wire is 22.42 feet

The distance from the base of the pole to the spot where the wire touches the ground is 16.66 feet

Step-by-step explanation:

* Lets explain the situation in the problem

- The telephone pole , the wire and the ground formed a right triangle

- The wire is the hypotenuse of the triangle

- The height of the telephone pole and the distance from the base of

 the pole to the spot where the wire touches the ground are the legs

 of the triangle

- The angle between the wire and the ground is 42°

- The angle 42° is opposite to the height of the telephone pole

- The height of the telephone pole is 15 feet

* Lets use the trigonometry functions to find the length of the wire

 (hypotenuse) and the distance from the base of the pole to the spot

 where the wire touches the ground

∵ sin Ф = opposite/hypotenuse

∵ Ф = 42° and its opposite side = 15 feet

∴ sin 42 = 15/hypotenuse ⇒ by using cross multiplication

∴ sin 42° (hypotenuse) = 15 ⇒ divide both sides by sin 42

∴ hypotenuse = 15/sin 42° = 22.42 feet

∵ The length of the wire is the hypotenuse

∴ The length of the wire is 22.42 feet

∵ The distance from the base of the pole to the spot where the wire

   touches the ground is the adjacent side to the angle 42°

∵ tan Ф = opposite/adjacent

∴ tan 42° = 15/adjacent ⇒ by using cross multiplication

∴ tan 42° (adjacent) = 15 ⇒ divide both sides by sin 42

∴ adjacent = 15/tan 42° = 16.66 feet

∵ The adjacent side is the distance from the base of the pole to the

  spot where the wire touches the ground

∴ The distance from the base of the pole to the spot where the wire

   touches the ground is 16.66 feet

7 0
3 years ago
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