Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
Answer:
B: She is incorrect because the segments do not have the same length.
Step-by-step explanation:
Answer:
63
Step-by-step explanation:
2+1= 3
15-3= 12
12 x 3 = 36
99 - 36
= 63
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Answer:
16
Step-by-step explanation:
You have: 14 / (7/8)
To divide by fractions, all you have to do is take the reciprocal of the second number, aka flip it
so, if you do that, you get 14 * 8/7
14*8=112, and 112/7 is 16
