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serious [3.7K]
3 years ago
13

Line perpendicular to y=2/3+3 and passes through 2,1

Mathematics
1 answer:
Vlad [161]3 years ago
7 0
I'm assuming there is an x after 2/3?

y = (2/3)x + 3


First we invert the gradient to make it perpendicular.

y = (-3/2)x + 3


Now we need to make y equal to 1, when x is 2. Currently, y is 0, since (-3/2) * 2 is -3, plus 3 is 0. We could just add 4 instead of 3 to make y equal to 1, so the line...

y = (-3/2)x + 4

is perpendicular to the line you provided, and passes through (2, 1).
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4x - 3 = 5 X=? can anyone tell me please
vekshin1

Answer:

x = 2

Step-by-step explanation:

4x - 3 = 5

4x = 8

x = 8/4

x = 2

------------

4 (2) - 3 = 5

8 - 3 = 5

5 = 5

answer: x = 2

7 0
2 years ago
Given triangle ABC with vertices A(16,0), B(9,2), and C(2,0).
Margaret [11]
Given:

Triangle Point coordinates or vertices:
A(16,0)
B(9,2)
C(2,0)

Required:

Side with slope -2/7

Solution:

To know which side has the slope required, we need to calculate the slope of each paired point by the two-point slope formula:

m = (y2-y1)/(x2-x1)

We first try points A and B.

m1 = (2-0)/(9-16)

m1 = -2/7

Thus, the side with the slope -2/7 is side AB.
4 0
3 years ago
4 Helen drew the pattern shown in a
omeli [17]

Answer:

50%

Step-by-step explanation:

5 0
3 years ago
Factorise 2xy²+8y please ​
OverLord2011 [107]

Answer:

Step-by-step explanation

2xy² +8y

= 2y (xy+8)

Just see what is the maximum common numbers u can find

5 0
3 years ago
Read 2 more answers
A maker of a certain brand of low-fat cereal barsclaims that the average saturated fat content is 0.5gram. In a random sample of
finlep [7]

Answer:

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

p_v =2*P(t_{(7)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=0.475

The sample deviation calculated s=0.183

We need to conduct a hypothesis in order to check if the true mean is 0.5 or no, the system of hypothesis would be:  

Null hypothesis:\mu = 0.5  

Alternative hypothesis:\mu \neq 0.5  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{0.475-0.5}{\frac{0.183}{\sqrt{8}}}=-0.386    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=8-1=7  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(7)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is different from 0.5 at 5% of signficance.  So then the claim makes sense

4 0
3 years ago
Read 2 more answers
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