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serious [3.7K]
3 years ago
13

Line perpendicular to y=2/3+3 and passes through 2,1

Mathematics
1 answer:
Vlad [161]3 years ago
7 0
I'm assuming there is an x after 2/3?

y = (2/3)x + 3


First we invert the gradient to make it perpendicular.

y = (-3/2)x + 3


Now we need to make y equal to 1, when x is 2. Currently, y is 0, since (-3/2) * 2 is -3, plus 3 is 0. We could just add 4 instead of 3 to make y equal to 1, so the line...

y = (-3/2)x + 4

is perpendicular to the line you provided, and passes through (2, 1).
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Dimas [21]

Answer:

18.457

Step-by-step explanation:

6 0
2 years ago
Can anyone help me on this? thank u,, brainliested :))
Travka [436]

Answer:

Put a pretend dot at number 2 and number -4, then since the line is undefined, it will simply be vertical and look like this:

3 0
3 years ago
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Mariulka [41]
I believe the answer is B. 39, 49, 59
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3 years ago
Someone please help me on number 3 and if the others are wrong please let me know ITS MULTI STEP EQUATION COMBINING LIKE TERMS
weeeeeb [17]

Answer:

#1: x = 3; #2 c = 1/2; #3 = x = 22; #4 is correct (x = -8)

Step-by-step explanation:

for the first equation everything was right until 22x = 66

after

22x = 66

you must divide everything by 22

x = 3

that is for #1

for the second equation you copied down the question wrong

the negative is still there

6c - 8 - 2c = -6

combine 6c and -2c

4c - 8 = -6

the negative remains on the 8

add 8 to both sides

4c = 2

divide 4 to both sides

c = 2/4 or just 1/2

for the third equation you must first combine like terms

-3x + 25 + x + 21 = 2

combine -3x and x & 25 and 21

-3x + x = -2x

25 + 21 = 46

-2x + 46 = 2

then subtract 46 from both sides

-2x = -44

now divide both sides by -2

x = 22

that is your answer

number four should be correct

3 0
1 year ago
What is the scale factor of a when it has a length of 12 and width of 8
Marta_Voda [28]

Answer:

wag kana mag module sunugin mo nalang

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