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3 years ago

14

I need help hurry i really need help thx you to over helps me

1 answer:

AlladinOne [14]3 years ago

5 0

Answer:

The answer is A.

Step-by-step explanation:

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HELP ME, PLZ. 100 POINTS !!!

marta [7]

Answer:

x=2√5/5

x=-2√5/5

Step-by-step explanation:

13√(2√5/5)^2-(2√5/5)^4+9√(2√5/5)^2+(2√5/5)^4=16

13√(4×5/25)-(16×25/625)+9√(4×5/25)+(16×25/625)

13√(4/5)-(16/25)+9√(4/5)+(16/25)

13√(4/25)+9√(36/25)

13×2/5+9×6/5

26/5+54/5

16=16 (proven)

3 0

2 years ago

Which of these rational numbers is also an integer?

dexar [7]

Answer:

6/3

Step-by-step explanation:

An integer is a whole number, that is not a fraction. All of the numbers are fractions, but if you simplify them, you see that 6/3=2. 2 is a whole number, and therefore an integer.

3 0

2 years ago

Read 2 more answers

Find the area.........

rodikova [14]

Answer:

211 cm

Step-by-step explanation:

upper rectangle + lower rectangle (11-8=3) + end triangles

(8x20) + (3x12) + (1/2x3x5 each x2)

160+36+15=211

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2 years ago

A like has two-fold Symmetry

Vikki [24]

Answer:

yes

Step-by-step explanation:

5 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago