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nikdorinn [45]
3 years ago
13

A nurse collected data about the average birth weight of babies in the hospital that month. Her data is shown using the dot plot

. Create a box plot to represent the data. dot plot titled Monthly Birth Weight and number line from 8 to 9 in increments of 1 tenth labeled Birth Weight (in pounds.) with zero dots over 8, zero dots over 8 and 1 tenth, 2 dots over 8 and 2 tenths, 2 dots over 8 and 3 tenths, 2 dots over 8 and 4 tenths, 3 dots over 8 and 5 tenths, zero dots over 8 and 6 tenths, 1 dot over 8 and 7 tenths, zero dots over 8 and 8 tenths, 1 dot over 8 and 9 tenths, and zero dots over 9 box plot with minimum value 8 and 3 tenths, lower quartile 8 and 4 tenths, median 8 and 5 tenths, upper quartile 8 and 6 tenths, and maximum value 8 and 9 tenths box plot with minimum value 8 and 2 tenths, lower quartile 8 and 3 tenths, median 8 and 4 tenths, upper quartile 8 and 5 tenths, and maximum value 8 and 9 tenths box plot with minimum value 8 and 3 tenths, lower quartile 8 and 5 tenths, median 8 and 6 tenths, upper quartile 8 and 7 tenths, and maximum value 8 and 9 tenths box plot with minimum value 8 and 2 tenths, lower quartile 8 and 3 tenths, median 8 and 4 tenths, upper quartile 8 and 6 tenths, and maximum value 8 and 9 tenths
Mathematics
1 answer:
mixer [17]3 years ago
5 0

Answer:

The values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

Step-by-step explanation:

The data provided is as follows:

X     Frequency

8        0

8.1        0

8.2        2

8.3        2

8.4        2

8.5        3

8.6        0

8.7         1

8.8        0

8.9         1

 9           0

So, the actual data is:

S = {8.2 , 8.2 , 8.3 , 8.3 , 8.4 , 8.4 , 8.5 , 8.5 , 8.5 , 8.7 , 8.9 }

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  1. Minimum (shown at the bottom of the chart)
  2. First Quartile (shown by the bottom line of the box)
  3. Median (or the second quartile) (shown as a line in the center of the box)
  4. Third Quartile (shown by the top line of the box)
  5. Maximum (shown at the top of the chart).

The data set is arranged in ascending order.

The minimum value is, Min. = 8.2

The lower quartile is,

[\frac{n+1}{4}]^{th}\ obs.=[\frac{11+1}{4}]^{th}\ obs.=3^{rd }\ obs. =8.3,

Q₁ = 8.3.

The median value is,

[\frac{n+1}{2}]^{th}\ obs.=[\frac{11+1}{2}]^{th}\ obs.=6^{th}\ obs.=8.4

Median = 8.4

The upper quartile is,

[\frac{3(n+1)}{4}]^{th}\ obs.=[\frac{3(11+1)}{4}]^{th}\ obs.=9^{th }\ obs. =8.5,

Q₃ = 8.5.

The maximum value is, Max. = 8.9.

So, the values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

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Kipish [7]

Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = \frac{x}{2}

2 years more than half of April's age = \frac{x}{2}+2

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$\Rightarrow \ \ x+(\frac{x}{2}+2) =23

$\Rightarrow \ \ x+\frac{x}{2}+2 =23

$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

$\Rightarrow \ \ \frac{x\times2}{1\times2}+\frac{x}{2}+\frac{2\times2}{1\times2} =23

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Denominators are same, now add the fractions.

$\Rightarrow \ \ \frac{2x+x+4}{2} =23

Do cross multiplication.

$\Rightarrow \ \ 2x+x+4=23\times2

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Laura's age = 9

Hence Laura's age is 9 years.

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3 years ago
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