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alina1380 [7]
2 years ago
11

What is the next fraction in this sequence? Simplify your answer. 5/6, 2/3, 1/2, 1/3, ...

Mathematics
2 answers:
natali 33 [55]2 years ago
7 0

Answer:

The fifth sequence is 1/6

Lerok [7]2 years ago
6 0

Answer:

it could be anything under 1/3

Step-by-step explanation:

so 1/5, 1/4, 1/6 ... etc

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peter buys 8.5 square feet of carpet. the carpet cost $10.20 cents per square foot. how much does peter pay for the carpet?
Fiesta28 [93]
10.20*8= 81.60
10.20*.5= 5.10
add
81.60+5.10= 86.70
ANSWER: Peter pays $86.70 for the carpet
5 0
3 years ago
Solve for x: |4x + 12| = 16
JulijaS [17]
4x+12=16
4x=4
x=1

or

-(4x+12)=16
-4x-12=16
-4x=28
x=-7

answer Choice C is correct
6 0
3 years ago
Read 2 more answers
Two trains started moving at the same time, train A from Boston to New York, and train B from New York to Boston. The distance b
Ede4ka [16]

Answer:

  • <u>After 1.7 hours</u>

Explanation:

<u>1. Calculate the average speed of train B</u>

  • 60mph = 3/4 (s) ⇒ s = 60 (4/3) mph = 80 mph

<u>2. Build a table</u>

When the two trains meet:

Train     Average speed     Distance       time (distance/average speed)

                 mph                            

A                 60                             x                        x/60

B                 80                        240 - x                (240 - x) / 80

<u>3. Write the equation</u>

The time, when the two trains meet, is the same for both trains:

                  \dfrac{x}{60}=\dfrac{240-x}{80}\\ \\ \\ 80x=14,400-60x\\ \\ 80x+60x=14,400\\ \\ 140x=14,400\\ \\ x=14,400/140\\ \\ x=102.85miles

<u>4. Calculate the time:</u>

  • x/60 = 102.86 / 60 = 1.7 hours

The two trains will meet after 1.7 hours

7 0
2 years ago
Can you help with this?
g100num [7]

Answer:

c or d

Step-by-step explanation:

good luck

hope this helps

need more answer? just follow me

and it will be nice if i get Brainliest!!

8 0
3 years ago
One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst
grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let <em>X</em> = number of telephone calls.

The average number of calls per minute is, <em>λ</em> = 3.0.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.0.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...

(a)

Compute the probability of <em>X</em> = 0 as follows:

P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498

Thus, the  probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of <em>X</em> > 5  as follows:

P (X > 5) = 1 - P (X ≤ 5)

              =1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of <em>X</em> = 3 as follows:

<em> </em>P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09<em />

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

Compute the probability of <em>X</em> ≤ 1 as follows:

P (X ≤ 1 ) = P (X = 0) + P (X = 1)

             =\frac{e^{-1.5}1.5^{0}}{0!}+\frac{e^{-1.5}1.5^{1}}{1!}\\=0.2231+0.3347\\=0.5578

Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

5 0
3 years ago
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