Let's say, the first number is "n"
well, the consecutive number of "n" is "n + 1"and the consecutive number of "n+1" is "n + 1" +1 or n + 2
so, the numbers are (n), (n+1) and (n+2), whatever "n" is
now, the sum of their squares is 116
expand the binomials by FOIL or binomial theorem, and then simplify
well, the consecutive number of "n" is "n + 1"and the consecutive number of "n+1" is "n + 1" +1 or n + 2
so, the numbers are (n), (n+1) and (n+2), whatever "n" is
now, the sum of their squares is 116
expand the binomials by FOIL or binomial theorem, and then simplify