Given the formula I=prt, if p = 8000, r = 0.6, and t = 1, what is the value of "I"?

2 answers:

max2010maxim [7]3 years ago

7 0

Because you have the formula, it is pretty easy to answer.
l=prt, so you plug in p, r, and t to get l.
1) l = 8000 times 0.6 times 1
2) you would then get 4800 times 1
3) Now you have 4800 because 4800 times 1 is 4800.

l = 4800

alexandr402 [8]3 years ago

6 0

Well, 8000 (p) * 0.6 (r) = 4800, and if you multiply that by 1 (t) it's still 4800. So the value of I is 4800.

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$\text{The vertex form of a quadratic equation}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-\text{vertex}\\=====================================$

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$\bold{METHOD\ 2:}\\\\\text{Use the formulas:}\ h=\dfrac{-b}{2a},\ k=f(k)\\\\f(x)=x^2+2x-3\to a=1,\ b=2,\ c=-3\\\\h=\dfrac{-2}{2(1)}=\dfrac{-2}{2}=-1\\\\k=f(-1)=(-1)^2+2(-1)-3=1-2-3=-4\\\\f(x)=(x-(-1))^2-4=(x+1)^2-4$