Answer:
System of equations:
Augmented matrix:
![\left[\begin{array}{cccc}1&2&2&6\\2&1&1&6\\1&1&3&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C2%261%261%266%5C%5C1%261%263%266%5Cend%7Barray%7D%5Cright%5D)
Reduced Row Echelon matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%261%261%262%5C%5C0%260%261%261%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Convert the system into an augmented matrix:
For notation, R_n is the new nth row and r_n the unchanged one.
1. Operations:
Resulting matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&-3&-3&-6\\0&-1&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%26-3%26-3%26-6%5C%5C0%26-1%261%260%5Cend%7Barray%7D%5Cright%5D)
2. Operations:
Resulting matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&-1&1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%261%261%262%5C%5C0%26-1%261%260%5Cend%7Barray%7D%5Cright%5D)
3. Operations:
Resulting matrix:
![\left[\begin{array}{cccc}1&2&2&6\\0&1&1&2\\0&0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%262%266%5C%5C0%261%261%262%5C%5C0%260%262%262%5Cend%7Barray%7D%5Cright%5D)
4. Operations:
Resulting matrix:
Answer:
42 times.
Step-by-step explanation:
The number of total alphabet = 26 tiles
The number of vowels = 5
The number of consonant = 26 - 5 = 21
Sofia will randomly select 1 tile from the bag and without replacement select another tile from the bag.
The probability to select consonant at first time = 21/26
Total tiles after the first selection = 26 - 1 = 25
The probability to select vowels at second time = 5/25
The probability to select consonant and vowels = 
Sofia will draw two tiles from the bag 260 times.
The prediction for the number of times Sofia will select a consonant tile and a vowel tile = 
Answer:
<h2>d(4) = 64</h2>
Step-by-step explanation:
d(1) = 13
d(n) = d(n - 1) + 17
where
n is the nth term
To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term
So we have
<u>For the 2nd term</u>
That's d(2)
We have
d(2) = d(2-1) + 17
d(2) = d(1) + 17
But d(1) = 13
d(2) = 13 + 17 = 30
<u>For the 3rd term d(3)</u>
That's
d(3) = d(3 - 1) + 17
d(3) = d(2) + 17
d(3) = 30 + 17 = 47
<u>For the 4th term that's d(4)</u>
We have
d(4) = d(4 - 1) + 17
d(4) = d(3) + 17
d(4) = 47 + 17
We have the final answer as
<h3>d(4) = 64</h3>
Hope this helps you
Answer:
MON= 57
Step-by-step explanation:
5x-23+3x-15=90
8x-38=90
8x=128
x=16
PLUG 16 INTO MON EQUATION
5(16)-23=57
therefore,
MON=57
USE COMPLEMENTARY FOR PROBLEMS LIKE THIS :)))
(btw, assuming that the angle is 90 degrees)
Answer:No it cannot,
Step-by-step explanation:
A prime number is any number that is pime doesnt matter what number as long as it is a prime number it can be a multiple techically,but not offen depends but in this case most likely not
