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vladimir2022 [97]
4 years ago
6

Which expressions show repeated multiplication? Check all that apply.

Mathematics
1 answer:
Westkost [7]4 years ago
3 0

Answer:

Step-by-step explanation:

2,3 and 5

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Step-by-step explanation:

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Answer:

C

Step-by-step explanation:

y = 2x + 5

the slope (m) of this line is 2 (which can be written as 2/1)

The slope of a perpendicular line is -1/m (the reciprocal of the slope with the opposite sign)

so m = 2/1 => -1/m = - 1/2 = the slope of a line perpendicular to y = 2x + 5

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Answer:

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8 0
3 years ago
Examine the following system of inequalities.
topjm [15]
<h2>Answer:</h2>

Dotted linear inequality shaded below passes through (0, 4) & (4,3). Dotted parabolic inequality shaded above passes through points (negative 6,4), (negative 4, 0) & (negative 2, 4).

<h2>Step-by-step explanation:</h2>

Hello! Let me help you to find the correct option to this problem. First of all, we have the following system of inequalities:

\left\{ \begin{array}{c}y< -\frac{1}{4}x+4\\y>(x+4)^{2}\end{array}\right.

To solve this, let's write the following equations:

<h3>FIRST:</h3>

y=-\frac{1}{4}x+4

This is a linear function written in slope-intercept form as y=mx+b. So, the slope m=-\frac{1}{4} and the y-intercept is b=4. Since in the inequality we have the symbol < then the graph of the line must be dotted. To get the shaded region, let's take a point, say, (0, 0) and let's test whether the region is above or below the graph. So:

y< -\frac{1}{4}x+4 \\ \\ Let \ x=y=0 \\ \\ 0

Since the expression is true, then the region is the one including point (0, 0), that is, it's shaded below.

<h3>SECOND:</h3>

y=(x+4)^{2}

This is a parabola that opens upward and whose vertex is (-4,0). Since in the inequality we have the symbol > then the graph of the parabola must be dotted. Let's take the same point (0, 0) to test whether the region is above or below the graph. So:

y>(x+4)^{2} \\ \\ Let \ x=y=0 \\ \\ 0>(0+4)^2\\ \\ 0>16 \ False!

Since the expression is false, then the region is the one that doesn't include point (0, 0), that is, it's shaded above

____________________

<h3>On the other hand, testing points (0, 4)  and (4,3) on the linear function:</h3>

y=-\frac{1}{4}x+4 \\ \\ \\ \bullet \ (0,4): \\ \\ y=-\frac{1}{4}(0)+4 \therefore y=4 \\ \\ \\ \bullet \ (4,3): \\ \\ y=-\frac{1}{4}(4)+4 \therefore y=3

So the line passes through these two points.

<h3 /><h3>Now, testing points (negative 6,4), (negative 4, 0) & (negative 2, 4) on the parabola:</h3><h3 />

y=(x+4)^2 \\ \\ \\ \bullet \ (-6,4): \\ \\ y=(-6+4)^2 \therefore y=(-2)^2 \therefore y=4 \\ \\ \\ \bullet \ (-4,0): \\ \\ y=(-4+4)^2 \therefore y=0 \\ \\ \\ \bullet \ (-2,4): \\ \\ y=(-2+4)^2 \therefore y=(2)^2 \therefore y=4

So the line passes through these three points.

Finally, the shaded region is shown below.

6 0
3 years ago
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