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igomit [66]
3 years ago
5

A briefcase has a three- digit lock code that doesn't include zero as a digit. What is the probability that the lock code consis

ts of all even digits if the same digit is not used more than once.
Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer:

1/21.

Step-by-step explanation:

There are 9 digits and the total number of permutations of 3 from 9 is 9P3

= 9!/6!  = 504.

There are 4 even digits so the number of permutations of 3 from these 4 is 4!  (4-3)!  = 4*3*2 = 24.

So the required probability =  24/504

= 1/21.

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Complete the function for this graph.
Solnce55 [7]

Answer:

y=|x-(-2)|+2

Step-by-step explanation:

Hope this is helpful.

5 0
3 years ago
Factorise the following expression using grouping and use binomial products to simplify.
rewona [7]

Answer:

11x-55-5a+ax

11(x-5)+a(x-5)

(11+a)(x-5)

Step-by-step explanation:

First you factor out the common factors

for(11x-55) is would be 11 as both of these figures are the multiple of 11

for(ax-5a) the common factor is a which will be factor out

Then after doing the process you will get

11(x-5)+a(x-5)

then factor out(x-5)which will give you

(11+a)(x-5)

6 0
3 years ago
Read 2 more answers
Help me with this problem for my quiz pls
Murljashka [212]

Answer:

9

Step-by-step explanation:

2 raised by 3 = 8

4 * 2 = 8

8 + 8 = 16

16 - 7 = 9

4 0
2 years ago
An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d
anygoal [31]

Answer:

The probability of event <em>A</em> is \frac{7}{11}.

The probability of event <em>B</em> is \frac{6}{11}.

Step-by-step explanation:

The sample space of rolling a fair six-sided dice is as follows:

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

      (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

      (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

      (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

      (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

      (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

Now consider the experiment of the computing the sum of the two rolls as follows:

X = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

Number of total outcomes, <em>N</em> = 11.

The probability of an event <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The event <em>A</em> is defined as the sum is greater than 5.

The sample space of <em>A</em> is:

A = {6, 7, 8, 9, 10, 11, 12}

n (A) = 7

Compute the probability of event <em>A</em> as follows:

P(A)=\frac{n(A)}{N}=\frac{7}{11}

Thus, the probability of event <em>A</em> is \frac{7}{11}.

The event <em>B</em> is defined as the sum is an even number.

The sample space of <em>B</em> is:

B = {2, 4, 6, 8, 10, 12}

n (B) = 6

Compute the probability of event <em>B</em> as follows:

P(B)=\frac{n(B)}{N}=\frac{6}{11}

Thus, the probability of event <em>B</em> is \frac{6}{11}.

7 0
3 years ago
The line shown below are parallel if the green line has a slope of -4 where is the slope of the redline
NemiM [27]

Answer:

-4

Step-by-step explanation:

Parallel lines have the same slope

If the green line has a slope of -4, then the red line has a slope of -4

4 0
3 years ago
Read 2 more answers
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