Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Answer:
A
Step-by-step explanation:
Because this ia so simple I don't even need to explain to waste my last few brain cells.
Answer:
77
Step-by-step explanation:
Firstly, we need to calculate the total score of the junior students and the total score of the senior students.
The total score of the junior students is 35 * 80 = 2,800
The total score of the senior students is 15 * 70 = 1050
The total score is thus 2,800 + 1,050 = 3,850
The average score of the 50 students is thus 3,850/50 which equals 77
Answer:
Step-by-step explanation:
6⁻︎¹(4⁻︎²)
1/6x1/4 2
1/6 x 1/16
1/96
Answer:
Step-by-step explanation:
There are only 2 solutions for none of the rooks can capture any of the other rooks: only if they are laid out in either of the 2 diagonal of the chess board
The number of possible combination for the rock to laid out in 8x8 (64 slots) chess board
possible combination
So the probability is pretty thin
