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svlad2 [7]
3 years ago
7

The heights, in inches, of several seventh-grade students at Evan Mills Middle School are listed below.

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
Does this help?
i did it online so i don't know if it's what you need or not, hopefully it is though. :)

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3x - 4y - 1=0
olchik [2.2K]

Answer:

  solvable

Step-by-step explanation:

The coefficients of x and y have different ratios, so the equations are solvable.

__

The solution is (x, y) = (7/15, 1/10).

3 0
3 years ago
PLEASE HELP PERSONAL FINANCE / LAUNCH QUESTION
Kobotan [32]

Answer:

option d: 25% unfavorable

Step-by-step explanation:

The budget is $40, and it was spent $50, so as the amount spent was higher than the budget, we have a unfavorable percent of variance.

The amount spent more than the budget was:

50 - 40 = 10

Now to calculate the percent of variance, we divide the value spent more than the budget (10) by the value of the budget (40)

Percent of variance = 10 / 40 = 0.25 = 25%

So the answer is 25% unfavorable, option d

3 0
3 years ago
Find the values of p and q such that 4x^2+12x=4(x+p)^2-q
-Dominant- [34]

Answer:

p = 1.5 and q = 9

Step-by-step explanation:

Expand the right side then compare the coefficients of like terms on both sides, that is

4(x + p)² - q ← expand (x + p)² using FOIL

= 4(x² + 2px + p²) - q ← distribute parenthesis

= 4x² + 8px + 4p² - q

Comparing coefficients of like terms on both sides

8p = 12 ( coefficients of x- terms ) ← divide both sides by 8

p = 1.5

4p² - q = 0 ( constant terms ), that is

4(1.5)² - q = 0

9 - q = 0 ( subtract 9 from both sides )

- q = - 9 ( multiply both sides by - 1 )

q = 9

7 0
3 years ago
The conference will begin at 8:30 a.m. and will last 5 hours 45 minutes. What time will the conference be over?
Delicious77 [7]

Add the time to the start time:

8:30

1 hour: 9:30 am

2 hours: 10:30am

3 hours: 11:30am

4 hours: 12:30pm

5 hours: 1:30pm

Then 45 minutes makes the time 2:15pm

Answer: 2:15 pm

3 0
3 years ago
Help ASAP!!!! Thanks
Tema [17]

Answer:

No DB is not a perpendicular bisector of AC

Step-by-step explanation:

This is because as AC is a straight line it's angle degree is 180 which when bisected by DB becomes,

180 ÷ 2 = 90

On both the angles i.e <BDC = <NDA = 90°

To make it a perpendicular bisector but

<BDC is not equal to <NDA is not equal to 90°.

Hence, DB is not a perpendicular bisector of line AC.

8 0
3 years ago
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