Answer:
A. The distribution of sample means of the differences will be approximately normal if there are at least 30 years of data in the sample and/or if the population of differences in winning times for all years is normal.
Step-by-step explanation:
In other to perform a valid paired test, one of the conditions required is that, data for both groups must be approximately normal. To attain normality, the population distribution for the groups must be normal or based on the central limit theorem, the sample size must be large enough, usually n > 30. Hence, once either of the two conditions are met, the paired sample will be valid.
What is the equasion then i can tell u the answer
Answer:
a) H0: 
H1: 
b) 
And the critical values with 
on each tail are:
c) ![t=(10-1) [\frac{1.186}{1.34}]^2 =7.05](https://tex.z-dn.net/?f=%20t%3D%2810-1%29%20%5B%5Cfrac%7B1.186%7D%7B1.34%7D%5D%5E2%20%3D7.05)
d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Step-by-step explanation:
Information provided
n = 10 sample size
s= 1.186 the sample deviation
the value that we want to test
represent the p value for the test
t represent the statistic (chi square test)
significance level
Part a
On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:
H0:
H1:
The statistic is given by:
![t=(n-1) [\frac{s}{\sigma_o}]^2](https://tex.z-dn.net/?f=%20t%3D%28n-1%29%20%5B%5Cfrac%7Bs%7D%7B%5Csigma_o%7D%5D%5E2%20)
Part b
The degrees of freedom are given by:
And the critical values with on each tail are:
Part c
Replacing the info we got:
Part d
For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34
Answer:
Option C and D are correct.
Step-by-step explanation:
Area of rectangle = 144 cm^2
Width of rectangle = 9 cm
Length of rectangle = ?
We know,
Area of rectangle = Length * Width
144 = Length * 9
144/9 = Length
=> length = 16 cm
Option A is incorrect as 3 times width = 3* 9 = 27 but our length = 16 cm
Option B is incorrect as length = 16 cm and not 63 cm
Option C is correct as Length < 2(Width)
=> 16 < 2(9) => 16 < 18 which is true.
Option D is correct.
Perimeter = 2(Length + Width)
Perimeter = 2(16+9)
Perimeter = 50 cm
Option E is incorrect as Length ≠ Width
