Answer:
A
Step-by-step explanation:
The equation 5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0 is a quadratic equation
The value of x is 8 or 1
<h3>How to determine the value of x?</h3>
The equation is given as:
5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0
Rewrite as:
-5/x - 2 + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0
Take the LCM
[-5(x + 2) + (x -5)(x- 2)]\[x^2 - 4 + [3x + 8]/[x^2 - 4] = 0
Expand
[-5x - 10 + x^2 - 7x + 10]/[x^2 - 4] + [3x + 8]/[x^2 - 4] = 0
Evaluate the like terms
[x^2 - 12x]/[x^2 - 4] + [3x + 8]/[x^2 - 4 = 0
Multiply through by x^2 - 4
x^2 - 12x+ 3x + 8 = 0
Evaluate the like terms
x^2 -9x + 8 = 0
Expand
x^2 -x - 8x + 8 = 0
Factorize
x(x -1) - 8(x - 1) = 0
Factor out x - 1
(x -8)(x - 1) = 0
Solve for x
x = 8 or x = 1
Hence, the value of x is 8 or 1
Read more about equations at:
brainly.com/question/2972832
2x²-19x-33=0
(2x-22 )(2x.+3 ) = 0
(x-11)(2x+3)=0
x-11=0 implies x = 11
2x+3=0 implies x = -3/2
Answer:
![a_1=4\\\\a_2=0\\\\a_3=3](https://tex.z-dn.net/?f=a_1%3D4%5C%5C%5C%5Ca_2%3D0%5C%5C%5C%5Ca_3%3D3)
Explanation:
The equation is:
![a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}](https://tex.z-dn.net/?f=a_n%3D3a_%7Bn-1%7D-5a_%7Bn-2%7D-4a_%7Bn-3%7D)
and
![a_4=-7, a_5=-36, a_6=-85](https://tex.z-dn.net/?f=a_4%3D-7%2C%20a_5%3D-36%2C%20a_6%3D-85)
<u>1. Subsittute n = 6 into the equation:</u>
![a_6=3a_{5}-5a_{4}-4a_{3}](https://tex.z-dn.net/?f=a_6%3D3a_%7B5%7D-5a_%7B4%7D-4a_%7B3%7D)
Now subsititute the known values:
![-85=3(-36)-5(-7)-4a_{3}](https://tex.z-dn.net/?f=-85%3D3%28-36%29-5%28-7%29-4a_%7B3%7D)
You can solve for ![a_3](https://tex.z-dn.net/?f=a_3)
![-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3](https://tex.z-dn.net/?f=-85%3D-108%2B35-4a_%7B3%7D%5C%5C%5C%5C4a_3%3D12%5C%5C%5C%5Ca_3%3D12%2F4%5C%5C%5C%5Ca_3%3D3)
<u />
<u>2. Substitute n = 5 into the equation:</u>
![a_5=3a_{4}-5a_{3}-4a_{2}](https://tex.z-dn.net/?f=a_5%3D3a_%7B4%7D-5a_%7B3%7D-4a_%7B2%7D)
Substitute the known values and solve for ![a_2](https://tex.z-dn.net/?f=a_2)
![-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0](https://tex.z-dn.net/?f=-36%3D3%28-7%29-5%283%29-4a_%7B2%7D%5C%5C%5C%5C4a_2%3D-21-15%2B36%3D0%5C%5C%5C%5Ca_2%3D0)
<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>
<u />
![a_4=3a_{3}-5a_{2}-4a_{1}](https://tex.z-dn.net/?f=a_4%3D3a_%7B3%7D-5a_%7B2%7D-4a_%7B1%7D)
![-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4](https://tex.z-dn.net/?f=-7%3D3%283%29-5%280%29-4a_%7B1%7D%5C%5C%5C%5C4a_1%3D9%2B7%3D16%5C%5C%5C%5Ca_1%3D4)