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Marta_Voda [28]
3 years ago
9

Help me pleaseeeeeeee​

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0
ANSWER- Quinten’s is running between 0 and 8 hours from the start time

EXPLANATION- The question asks for the domain. We know that the domain comes from the x-axis. Since we were given that the x-axis represents time (which goes from 0 to 8) the correct answer is the third choice.
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Daisy works at an ice-cream parlor. She is paid $10 per hour for the first 8 hours she works in a day. For every extra hour she
tester [92]

Answer:

The expression giving her net earnings for a day with more than 8 hours worked is X = 80 + 15H, where H means "extra hours worked".

Step-by-step explanation:

Given that Daisy works at an ice-cream parlor earning $10 per hour for the first 8 hours she works in a day, and 1.5 times her hourly wage for every extra hour she works, in order to know how much can she make in a day working more than 8 hours the following equation has to be made:

X = (8 x 10) + (H x (1.5 x 10))

X = 80 + 15H

Therefore, if Daisy works 13 hours, the equation works as follows:

X = 80 + 15x13

X = 80 + 195

X = 275  

3 0
3 years ago
PLEASE HELP PLEASE AS FAST AS POSSIBLE PLEASE HELP PLEASE
Pie

The answer is C) $1104.49

7 0
3 years ago
Graph the solutions of the inequality
Fiesta28 [93]

Answer:

The graph in the attached figure

Step-by-step explanation:

Graph the solution of the inequality

t\leq -4

we know that

The solution is the interval ---> (-∞,-4]

All real numbers less than or equal to -4

In a number line the solution is the shaded area at left of t=-4 (closed circle, because the number -4 is included in the solution))

using a graphing tool

The graph in the attached figure

6 0
4 years ago
Combine the following fractions by addition or subtraction as directed.
Marina86 [1]
Answer:\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}

Explanation:

Combining the fractions, we have:

\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\  \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\  \\ =\frac{-6(x+y)}{xy(x-y)} \\  \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}

8 0
2 years ago
Please help me dirty birds, I don't understand
kow [346]

Answer:

A) Positive

B) Positive

C) None

D) Positive

Step-by-step explanation:

:)

7 0
4 years ago
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