Given :
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by 
.
To Find :
Find the time at which the concentration is a maximum. b. Find the maximum concentration.
Solution :
For maximum value of x, K'(x) = 0.
Since, time cannot be negative, so ignoring x = -3 .
Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6
Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.
Hence, this is the required solution.
1.
(Create a table then plot the points)
X | 0 | 1 | 2 | 3 |
-------------------------
Y | -1 | 3 | 7 | 11 |
4 (0) -1 => 0 - 1 = -1
4 (1) -1 => 4 - 1 = 3
4 (2) -1 => 8 - 1 = 7
4 (3) -1 => 12 - 1 = 11
Just apply the table method to the others and you should be fine! :)
Answer:
Graph the second equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis. At the point of intersection of the two equations x and y have the same values.
Answer:8x3/5=4.8
Step-by-step explanation:
Convert to a mixed number:
239/42
Divide 239 by 42:
4 | 2 | 2 | 3 | 9
42 goes into 239 at most 5 times:
| | | | 5
4 | 2 | 2 | 3 | 9
| - | 2 | 1 | 0
| | | 2 | 9
Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:
| | | | 5 | (quotient)
4 | 2 | 2 | 3 | 9 |
| - | 2 | 1 | 0 |
| | | 2 | 9 | (remainder)
The quotient of 239/42 is 5 with remainder 29, so:
Answer: 5 29/42
