From the moment the first car started how many hours will it take the second car to catch up to the first

Semeet uses 0.4 gallon of gasoline each hour moving lawns. how much gas does she use in 4.2 hours

laiz [17]

Answer:

I think the answer is 1 gallon of gas

Step-by-step explanation:

8 0

3 years ago

Laura has a rectangular piece of wood that is 7in by 4in she wants to cover it with strips of ribbon that are 1/4 inch wide what

inn [45]

Answer: 112 inches.

Step-by-step explanation:

You know that the width of the rectangular piece of wood is 4 inches and the width of the strip ribbon is 1/4 inches.

Then, let be "n" the number of strips ribbon that Laura needs to cover the width of the rectangular piece of wood (Assuming that she will cover the wood in the form shown in the figure attached). This is:

$n=\frac{4in}{\frac{1}{4}in}\\\\n=16$

To find the lenght of ribbon that Laura needs to conver the wood, you must multiply the number of strips ribbon "n" by the lenght of the rectangular piece of wood, then you get:

$lenght=(16)(7in)\\lenght=112in$

8 0

3 years ago

4(x + 3) = 6-x what is the answer I need help please

Amanda [17]

4(x + 3) = 6 - x

First, expand to remove parentheses.
$4x + 12 = 6 - x$
Second, subtract '6' from both sides.
$4x + 12 - 6 = -x$
Third, subtract '12 - 6' to get 6.
$4x + 6 = -x$
Fourth, subtract '4x' from both sides.
$6 = -x - 4x$
Fifth, since 'x' can be referred to as '1', add it to '4x' to get '-5x'.
$6 = -5x$
Sixth, divide both sides by '-5'.
$\frac{6}{-5} =x$
Seventh, change the whole fraction into a negative.
$-\frac{6}{5} =x$
Eighth, switch your sides.
$x = -\frac{6}{5}$

Answer as fraction: $-\frac{6}{5}$
Answer as decimal: -1.2

4 0

3 years ago

Glenn rode his bike for 2 hours

Natali5045456 [20]

Cool. I rode mine for 1.

5 0

3 years ago

Read 2 more answers

Inequality to x2 < 64

Anarel [89]

NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64 => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2 so (x^2) - (8^2) < 0 To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y) You can work backwards and verify this is true. so let's set (x^2) - (8^2) equal to zero to find the roots: (x^2) - (8^2) = 0 => (x-8)*(x+8) = 0 if x-8 = 0 => x=8 and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0 so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)

7 0

3 years ago