Answer:
3.4625
Step-by-step explanation:
Given the equation:
Q(t)=0.05t^2 + 0.1t + 3.4 parts per million
Where t = time in years
By approximately how much will the carbon monoxide lvel change during the coming 6 months?
t = 6 months = 6/12 = 0.5 year
Q(0.5) = 0.05(0.5)^2 + 0.1(0.5) + 3.4 parts per million
Q(0.5) = 0.05(0.25) + 0.05 + 3.4
Q(0.5) = 0.0125 + 0.05 + 3.4
Q = 3.4625
Carbon monoxide level will change by approximately 3.4625 parts per million in 6 months
The answer is Infinate Solutions I believe we are working on these types of equations in school rn
Answer:
2
Step-by-step explanation:
The 2 integers are 103 and 104
f(x) + c -> up by c
f(x) - c -> down by c
f(x + c) -> left by c
f(x - c) -> right by c
For y = f(x + c), the y value of x now takes the y value of the function of x + c, or the one c to the right of x, shifting the entire graph left by c.
Answer:
the answer is B there is no other possible answer that you can put.
Step-by-step explanation:
