Are u sure about the second arrow?BTW
Answer:
True
Step-by-step explanation:
Answer:
Hola
Step-by-step explanation:
Well if this is based off the first thing I answered, then 1. C
as I told you before, every time the x axis values go up one, the y values go up by x2 (aka times 2). Therefore it’s C.
2. It is linear because the unit change (amount it goes up aka slope) is the same since it’s alway x2. Hence the line on a graph would look linear
It is negative because the plot is going down not up
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.