Answer:
6638_729_88 and so this is what thay saif was right i leterkly just had to answer this
![\bf \cfrac{x}{4x+x^2}\implies \cfrac{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(4+x)}\implies \cfrac{1}{4+x}\qquad \{x|x\in \mathbb{R}, x\ne -4\}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%7D%7B4x%2Bx%5E2%7D%5Cimplies%20%5Ccfrac%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D%7D%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%284%2Bx%29%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B4%2Bx%7D%5Cqquad%20%5C%7Bx%7Cx%5Cin%20%5Cmathbb%7BR%7D%2C%20x%5Cne%20-4%5C%7D)
if you're wondering about the restriction of x ≠ -4, is due to that would make the fraction with a denominator of 0 and thus undefined.
I think it's 9 but I could be wrong
The midpoint of the line segment joining points S (8,3) and T (2,-1) is (5, 1)
<h3>How to determine the midpoint of the line segment joining the points?</h3>
The points are given as:
S(8,3) and T(2,-1)
The midpoint of the line segment joining points S(8,3) and T(2,-1) is calculated as:
Midpoint = 0.5 * (x1 + x2, y1 + y2)
So, we have
Midpoint = 0.5 * (8 + 2, 3 - 1)
Evaluate the sum
Midpoint = 0.5 * (10, 2)
Evaluate the product
Midpoint = (5, 1)
Hence, the midpoint of the line segment joining points S (8,3) and T (2,-1) is (5, 1)
Read more about midpoint at:
brainly.com/question/24311350
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