Answer:
both the groups have the same value for the first quartile
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
36 feet to metres = 10.97
first find the final velocity
vf^2 = vi^2 + 2ad
vf^2 = 0 + 2(9.81)(10.97)
vf^2 = 215.2314
vf = 14.6708
vf = vi + at
at = vf - vi
t = (vf - vi)/a
t = (14.6708)/9.81
t = 1.4955seconds
Answer:
Step-by-step explanation:
Split the area into two sections by extending 6 in segment.
We get a rectangle of 5 in x 10 in and a trapezoid.
<u>Rectangle:</u>
<u>Trapezoid:</u>
- A = 1/2(b₁ + b₂)h
- A = 1/2((15 - 5) + 7)*(10 - 6) = 1/2*17*4 = 34 in²
<u>Total area:</u>
Step-by-step explanation:
