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4 years ago

Maria is shopping for dog food. Brand A is 40-pound bag and cost $49. Brand B is 20-pound bag for $23.44

Mathematics

2 answers:

Marta_Voda [28]4 years ago

8 0

Answer:

brand a is $1.22 per pound. brand b is $1.17 per pound.

Step-by-step explanation:

brand b would be the cheapest per pound but brand a would be better because brand b would be doubled price wise to get the same amount as brand a.

elixir [45]4 years ago

6 0

Answer:

Brand B is cheaper than Brand A

Step-by-step explanation:

Brand A:

49/40=1.23

1.23*40=49

Brand B:

23.44/20=1.17

1.17*20=23.4

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nirvana33 [79]

Answer: Volume of an oblique cylinder is 2011.43 sq.m.

Step-by-step explanation:

Since we have given that

Radius of a cylinder = 8 meters

Height of a cylinder = 10 meters

Cavelieri's Principle states that volume of an oblique cylinder is same as the volume of right circular cylinder with equal radius and height.

As we know the formula for "Volume of cylinder":

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Hence, Volume of an oblique cylinder is 2011.43 sq.m.

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3 years ago

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Terry invested money in a biotech stock whose growth is modeled by the function f(x) = 0.01(2)x, where x represents number of da

strojnjashka [21]

Answer:

The average rate of change is 1.275

Step-by-step explanation:

The average rate of change of f(x) from x=a to x=b is given by:

$\frac{f(b)-f(a)}{b-a}$

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The average rate of change from day 2 to day 10 is given by:

$\frac{f(10)-f(2)}{10-2}$

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$=\frac{10.2}{8}=1.275$

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3 years ago

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Im pretty sure its $140 US Dollars
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4 years ago

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Step-by-step explanation:

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3 years ago

Use Euler's formula to derive the identity. (Note that if a, b, c, d are real numbers, a + bi = c + di means that a = c and b =

storchak [24]

Answer with Step-by-step explanation:

We have to prove that

$sin 2\theta=2sin\theta cos\theta$ by using Euler's formula

Euler's formula : $e^{i\theta}=cos\theta+isin\theta$

$e^{i(2\theta)}=(e^{i\theta})^2$

By using Euler's identity, we get

$cos2\theta+isin2\theta=(cos\theta+isin\theta)^2$

$cos2\theta+isin2\theta=(cos^2\theta-sin^2\theta+2isin\theta cos\theta)$

$(a+b)^2=a^2+b^2+2ab, i^2=-1$

$cos2\theta+isin2\theta=cos2\theta+i(2sin\theta cos\theta)$

$cos2\theta=cos^2\theta-sin^2\theta$

Comparing imaginary part on both sides

Then, we get

$sin2\theta=2sin\theta cos\theta$

Hence, proved.

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4 years ago