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nikklg [1K]
3 years ago
14

Use the the GCF to create an equivalent expression 18y + 24

Mathematics
1 answer:
Neporo4naja [7]3 years ago
3 0

Step-by-step explanation:

ingnore this like no cap ingnore this shiiii

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I think the answer is letter B.80
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If the life span of a light bulb is 2500 hours, approximately how many weeks can you
Tomtit [17]

● Answer:

~~ 15 weeks

● Step-by-step explanation:

1 week = 7 days = 7×24hours = 168 hours

2500 hours ÷ 168 hours = 14.88 hours

~~ 15 weeks

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3 years ago
What value of x is in the solution set of 8x-6>12+2x
Dimas [21]
The Answer to <span>8x-6>12+2x = x>3</span>
8 0
3 years ago
Read 2 more answers
Which statements describe transformations performed in f (x) = x^2 to create g (x) = 2x^2 + 5? select all that apply.
snow_tiger [21]

Answer:

The statements describe transformations performed in f(x) to create g(x) are:

a translation of 5 units up ⇒ c

a vertical stretch with a scale factor of 2 ⇒ d

Step-by-step explanation:

  • If f(x) stretched vertically by a scale factor m, then its image g(x) = m·f(x)
  • If f(x) translated vertically k units, then its image h(x) = f(x) + k

Let us use these rule to solve the question

∵ f(x) = x²

∵ g(x) is created from f(x) by some transformation

∵ g(x) = 2x² + 5

→ Substitute x² by f(x) in g(x)

∴ g(x) = 2f(x) + 5

→ Compare it with the rules above

∴ m = 2 and k = 5

→ That means f(x) is stretched vertically and translated up

∴ f(x) is stretched vertically by scal factor 2

∴ f(x) is translated 5 uints up

The statements describe transformations performed in f(x) to create g(x) are:

  • a translation of 5 units up
  • a vertical stretch with a scale factor of 2
8 0
2 years ago
A popular resort hotel has 300 rooms and is usually fully booked. About 7% of the time a reservation is canceled before the 6:00
kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that n = 300

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied.  So we use p = 0.93

Approximating the binomial to the normal.

E(X) = np = 300*0.93 = 279

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.93*0.07} = 4.42

The probability that at least 285 rooms will be occupied is 1 subtracted by the pvalue of Z when X = 285. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{285- 279}{4.42}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131.

So there is a 1-0.9131 = 0.0869 = 8.69% probability that at least 285 rooms will be occupied.

8 0
3 years ago
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