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frozen [14]
3 years ago
5

Does the point (5, 10) satisfy the inequality y>x+5

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
No, because if you plug in 10 for y and 5 for x then solve the inequality says 10>10
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HELP ITS SOO HARD also can you please explain how to get the answer to where a dummy can understand cuz well I’m a dummy
Ksenya-84 [330]

Answer:

244.92 square inches

Step-by-step explanation:

You just have to fill in the formula with the information they gave you.

They gave you the diameter for base circle so you divide that number in half to get the radius which is what you need for the formula represent as "r".

r=3

h=10

and you know pi is 3.14

so just plug in the numbers.

SA=2x3.14x3^2+2x3.14x3x10

SA=6.28x9+6.28x30

SA=56.52+188.4

SA=244.92

7 0
3 years ago
Help meee!!!!!!!!!!!!!!!!!!!
JulsSmile [24]

<u>-12+2-2i+2i</u>  

Simplify:  

10

<u>Answer:  </u>

<u>C: -10</u>

7 0
3 years ago
Read 2 more answers
Plss. pa answers ?<br><br>thanks po<br><br>​
Lana71 [14]

Answer:

<h3>Graph 3</h3>

Line starting at x = -2

  • <u>Domain</u>: x ≥ -2
  • <u>Range</u>: y ≥ 0
<h3>Graph 4</h3>

Vertical line

  • <u>Domain</u>: x = 3
  • <u>Range</u>: y = any real number
<h3>Graph 5</h3>

Quadratic function with negative leading coefficient and max value of 3

  • <u>Domain</u>: x = any real number
  • <u>Range</u>: y ≤ 3
<h3>Graph 6</h3>

Curve with non-negative domain and min value of -2

  • <u>Domain</u>: x ≥ 0
  • <u>Range</u>: y ≥ -2
<h3>Graph 7</h3>

Line with no restriction

  • <u>Domain</u>: x = any real number
  • <u>Range</u>: y = any real number
<h3>Graph 8</h3>

Quadratic function with positive leading coefficient and min value of 4

  • <u>Domain</u>: x = any real number
  • <u>Range</u>: y ≥ 4
<h3>Graph 9</h3>

Parabola with restriction at x = -4

  • <u>Domain</u>: x = any real number except -4
  • <u>Range</u>: y = any real number
<h3>Graph 10</h3>

Square root function with star point (2, 0)

  • <u>Domain</u>: x ≥ 2
  • <u>Range</u>: y ≥ 0
5 0
3 years ago
2/5(d−10)−2/3(d+6) is
MissTica
Remove parentheses
2/5 • d-10 - 2/3 • d+6

calculate
2/5d-4 - 2/3d-4

the answer
-4/15d-8
3 0
3 years ago
In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=2, what is
Alex777 [14]

Answer:

<em>The area of the shaded region is 3.</em>

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

A_s=2 * A_t

Where At is the area of each triangle.

\displaystyle A_t=\frac{AB*BC/2}{2}

\displaystyle A_t=\frac{AB*BC}{4}

We know AB=3 and BC=2, thus:

\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}

Simplifying:

\displaystyle A_t=\frac{3}{2}

Finally:

\displaystyle A_s=2 * \frac{3}{2}

A_s=3

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

3 0
3 years ago
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