100 hahahhahah yk what he
X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:


Step-by-step explanation:
<u>Given</u> :
4 cancels throughout.
<u>Solving by quadratic formula</u> :
- x = -8 ± √(8)² - 4(4)(-12) / 8
- x = -8 ± √64 + 192 / 8
- x = -8 ± √256 / 8
- x = -8 ± 16 / 8
- x = -1 ± 2
- x = 1 and x = -3
∴ Hence, the x-intercepts are (1, 0) and (-3, 0). The roots of the equation are 1 and -3.
In general the binomial expansion is

So in our case, because we want ascending powers of x we'll write,

We need to calculate the binomial coefficients:






1.5y < -6.75
First, divide both sides by '1.5'.
Second, since 4.5 × 1.5 = 6.5, simplify the fraction to '-4.5'

Answer:
y < -4.5