Answer:
To find the mode you need to check the number which is more often repeated in the set than the other.But as you can see here there is no number which is repeated more often than the other everyone is repeated once,so in this case we say that the set of data values has no mode.
To find the the range of the set of data you need to first place the numbers in ascending order (as it is already in) and then find the greatest and the smallest number and subtract them.
Range :
10,20,30,40,50,60,70,80,90,100,110,120,130,140,150.
Greatest number = 150.
Smallest number = 10.
Subtract = 150-10 = 140.
Step-by-step explanation:
F + V = E + 2
F = 25
V = 17
25 + 17 = E + 2
42 = E + 2
42 - 2 = E
40 = E <== there are 40 edges
Answer: The answer is dddddd
Step-by-step explanation:
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Answer:
$4.50
Step-by-step explanation:
Please give brainliest!!
3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
