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3 years ago

Find the length of line segmentAB which joins the following points.A(10, 14) and B(2,6)

Mathematics

1 answer:

Helen [10]3 years ago

5 0

Answer:

The equation of the line AB is y - x -4 = 0

Step-by-step explanation:

The points are A (10,14) and B(2,6)

Now, slope of the line AB : $m = \frac{y_2 - y_1}{x_2 - x_1}$

or, $m = \frac{14 -6 }{10 - 2}$ = $\frac{8}{8} = 1$

So, slope of the equation AB = 1

Now, by SLOPE INTERCEPT FORM:

The equation of line is given as : y - y0 = m (x-x0)

So,the equation of line AB is y - 6 = 1(x-2)

or, y - 6 -x + 2 = 0

or, y - x -4 = 0

Hence, the equation of the line AB is y - x -4 = 0

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Read 2 more answers

At high school basketball game, the athletic department sold 250 tickets and brought in 837.50. Adult tickets cost $5 and studen

Tpy6a [65]

Answer:

The system of equations is:

$a+s = 250\\5a+2.50s = 837.50$

Here a is the number of adult tickets and s is the number of student tickets

Step-by-step explanation:

We will use the given statements to make a system of equations for the given scenario.

First of all we have to decide which variables to be used.

Let a be the number of adult tickets and

Let s be the number of student tickets

So according to the statement that the department sold 250 tickets in total, the equation will be:

$a+s = 250$

This is equation one of the system of equations

According to the statement that cost of adult ticket is $5, total cost of adult tickets will be: $5a$

According to the statement that cost of student ticket is $2.50, total cost of student tickets will be: $2.50s$

The total earning was $837.50 so the second equation will be:

$5a+2.50s = 837.50$

Hence,

The system of equations is:

$a+s = 250\\5a+2.50s = 837.50$

Here a is the number of adult tickets and s is the number of student tickets

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3 years ago

Find the length of line segmentAB which joins the following points.A(10, 14) and B(2,6)​

Find the length of line segmentAB which joins the following points.A(10, 14) and B(2,6)