Question

The mother's age is 8 times her son's age. After 6 years, the age of the mother will be 9/2 times her son's age. The present ages of the son and the mother are, respectively

Answer 1

Answer:

s=6 years

m=48 years

Step-by-step explanation:

Let

Mother's age=m

Son's age=s

m=8*s

m=8s (1)

m+6=9/2(s+6)

m+6=9/2s+27 (2)

Substitute (1) into (2)

m+6=9/2(s)+27

8s+6=9/2s+27

8s+6-9/2s-27=0

8s-9/2s-21=0

(16-9/2)s-21=0

7/2s=21

s=21÷7/2

=21×2/7

=42/7

s=6

Present age of the son=6

m=8s

=8(6)

m=48

Present age of the mother=48