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Genrish500 [490]
3 years ago
15

Helpppppppoo!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Andru [333]3 years ago
8 0
I want to say its 6 but I'm not sure. sorry
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A composition of reflections over parallel lines is the same as a __________. A. translation B. rotation C. glide reflection D.
enyata [817]

Answer: A

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviat
tensa zangetsu [6.8K]

Answer:

0.6710

Step-by-step explanation:

The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviation is 5 millimeters.

Find the probability that the diameter of a selected bearing is between 104 and 115 millimeters. Round your answer to four decimal places.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 107 mm

σ is the population standard deviation = 5 mm

For x = 104 mm

z = 104 - 107/5

z = -0.6

Probability value from Z-Table:

P(x = 104) = 0.27425

For x = 115 mm

z = 115 - 107/5

z = 1.6

Probability value from Z-Table:

P(x = 115) = 0.9452

The probability that the diameter of a selected bearing is between 104 and 115 millimeters is calculated as:

P(x = 115) - P(x = 104)

0.9452 - 0.27425

= 0.67095

Approximately = 0.6710

8 0
3 years ago
PLEASE HELP ASAP ASAP
muminat

Answer:

slope = -1/12

Step-by-step explanation:

From the figure we can see that the line passes through 2 points which are

(-6,-1) and (6,-2)

Use the formula y2-y1/x2-x1

(-2-(-1))/6-(-6)

(-2+1)/6+6

-1/12

3 0
3 years ago
Select the correct answer.
Neporo4naja [7]

Answer:

c salary refers to the fixed amount paid on a weekly bi-weekly

5 0
3 years ago
Read 2 more answers
Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ > 0.
Ket [755]
You can use the trigonometric identity  1+\cot^2{x}=\csc^2{x}.

1+\cot^2{\theta}=(\frac{-\sqrt{37}}{6} )^2 \\ 1+\cot^2{\theta}=\frac{37}{36} \\ \cot^2{\theta}=\frac{1}{36} \\
\cot{\theta}=\frac{1}{6}

The requirement that \tan{\theta}\ \textgreater \ 0 eliminates -1/6 from being another solution.
6 0
3 years ago
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