Answer:
607 miltliters per day
Step-by-step explanation:
Step one:
given data
Kallie drank 12.75 gallons of water in 3 weeks
if she drank the same amount each day, then in one day she will drink
Note----there are 31 days in 3 weeks (7 days make 1 week)
Step two:
Hence in one day she will drink
= total volume of water/number of days
= 12.75/21
=0.607liters per day
or
607 militliters per day
Answer:
- domain: [1, 2) ∪ (2, 4) ∪ (4, 6]
- range: [1, 3) ∪ (3, 5) ∪ (5, 6]
Step-by-step explanation:
The open circles identify points where the function is <em>not defined</em>. They are excluded from both the domain and the range.
The domain is the horizontal extent of the function. This function is defined on the interval [1, 6], except at points x=2 and x=4, so those values need to be excluded from the domain.
The range is the vertical extent of the function. This function is defined between y=1 and y=6, excluding values y=3 and y=5. Those y-values will be excluded from the range.
In the interval notation used above, the curved bracket means the value is excluded. All values up (or down) to that are included, but that one is not. The square bracket means the end value is included in the interval.
Step-by-step explanation:
A.
Null hypothesis
H0: σ1² ≤ σ2²
Alternative hypothesis
H1: σ1² > σ2²
We have level of significance = 0.01
Test statistic
F = S1²/S2²
= 170²/100²
= 28900/10000
F = 2.89
Df = degrees of freedom
Df1 = n1 - 1
= 26-1
= 25
Df2 = n2 - 1
= 25-1
= 24
B. We get the p value using f distribution
Fdist(2.89,25,24)
P value = 0.0057
The p-value is less than 0.01 so we reject null hypothesis.
So we conclude that automobiles that are of 4 years have their variances to be larger In annual repair costs than those that are of 2 years.
Reasonableness: we expect this since 4byears old automobiles are more likely to have more expenses during repair leading to greater variances
2/3x-(-1)Answer:
Step-by-step explanation:
Answer:
b
Step-by-step explanation: