I don't know how to that i don't even know how to do my work
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Answer:
h = 8.588 m
Explanation:
Given:
Mass of hockey puck: m = 200 g = 0.2 K
g
Angle of incline: θ = 30º (with respect to horizontal)
Coefficient of static and kinetic friction between the puck and ramp:
μ
s = 0.4 and μk = 0.3
initial speed:
v = 3.5 m
/s
Let h be the vertical height reached by the puck, above the ground. This corresponds to a distance of
d = h
*sin 30º = 2
*h
along the incline. As the puck is moving, only kinetic friction comes into play as it climbs up the incline. Let N be the normal reaction exerted by the metal ramp on the ball. Then,
N = m*g
*cos θ = 0.2
*9.8
1*cos 30
º = 1.6991 N
Therefore, kinetic friction acting on the puck is:
F
k = μ
k
*N = 0.3
*1.6974 = 0.50974 N
From work energy theorem, the change in kinetic energy should equal the work done by friction and gravity. Therefore,
0.5* 0.2
*16² = 0.50974
*2h + 0.2*9.81*h
⇒ h = 8.588 m
Answer:
False
Explanation:
A web-based application encounters connectivity and compatibility relate to data server. It does not belong to any hardware environments.
A web based application is accessed over network.They run inside a web browser. Small of program is download to user's desktop, but this processing is done over internet.
Im not sure but i think its C at least two but once again im not sure hope this helps :)
