Answer:
Net force = 20 N
Explanation:
Given that,
Force acting on the left = 10 N
Force acting on the right = 30 N
Let right side is positive and left side is negative. Let the net force acting on the box is F. So,
F = -10+30
F = 20 N
So, the net force on the box is 20 N and it is in right side.
```
#!/usr/local/bin/python3
import sys
coins = { "quarters" : 25, "dimes" : 10, "nickels" : 5, "pennies" : 1 }
def mkChange( balance, coin ):
qty = balance // coins[ coin ]
if( qty ):
print( str( qty ) + ' ' + coin )
return( balance % coins[ coin ] )
if( __name__ == "__main__" ):
if( len( sys.argv ) == 2 ):
balance = int( sys.argv[ 1 ] )
balance = mkChange( balance, "quarters" )
balance = mkChange( balance, "dimes" )
balance = mkChange( balance, "nickels" )
balance = mkChange( balance, "pennies" )
else:
sys.stderr.write( "\nusage: " + sys.argv[ 0 ] + " <change owed>\n" )
```
Option B is what i would say
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